The distance between two fixed points is 6, and the sum of the squares of the distances from point m to these two fixed points is 26. Find the trajectory equation of point M

The distance between two fixed points is 6, and the sum of the squares of the distances from point m to these two fixed points is 26. Find the trajectory equation of point M


The midpoint of the line segment formed by these two points is the center, and the coordinate system is established
The coordinates of the two points are (- 3,0), (3,0) respectively. If the coordinates of the point m are (x, y), then according to the meaning of the title
[x-(-3)]^2+(y-0)^2+(x-3)^2+(y-0)^2=26
Simplify, simplify
x^2+y^2=4.



Given that the distance ratio between point m and two fixed points o (0,0), a (3,0) is 1 / 2, find the trajectory equation of point M
Given that the distance ratio of point m to two fixed points o (0,0), a (3,0) is 1 / 2, we can find the trajectory equation of point m. This is the problem we encountered when we studied the equation of circle


Let m (x, y)
Then am = 2om
So am ^ 2 = 4om ^ 2
That is, (x-3) ^ 2 + y ^ 2 = 4 (x ^ 2 + y ^ 2)
The trajectory equation of point m is (x + 1) ^ 2 + y ^ 2 = 4



Given that the distance between point m and X axis and the distance between point m and point F (0,4) are equal, the trajectory equation of point m is obtained


If M (x, y) is set as a moving point, then the distance between M and X axis and the distance between M and f (0, 4) are equal, that is, the trajectory equation of M is y = 18x2 + 2



Given that the distance from point m to point F (3,0) is 3 greater than the distance from point m to y-axis, the trajectory equation of point m is obtained,


It is known that the distance from point m to point F (3,0) is 3 times greater than the distance from point m to y-axis
Then the distance from point m to point F (3,0) is equal to the distance from it to the line x = - 3
So the trajectory of point m is a parabola
Let Y & # 178; = 2px
Then p / 2 = 3
So p = 6
So y & # 178; = 12x