Solving equation (1) 9 ^ (- x) - 2 * 3 ^ (1-x) = 27 (2) 6 ^ x + 4 ^ x = 9 ^ x

Solving equation (1) 9 ^ (- x) - 2 * 3 ^ (1-x) = 27 (2) 6 ^ x + 4 ^ x = 9 ^ x

(1) Let t = 3 ^ (- x), (T > 0), then the original formula can be changed to
t^2 -6t=27
Solution
T = 9, t = - 3 (rounding off)
X = 2 from 3 ^ (- x) = 9
(2) It's too difficult (I just worked out a number between 1 and 1)

Solving equation 9 ^ (- x) - 2 * 3 ^ (1-x) = 27

Let 3 ^ (- x) = a
Then 9 ^ (- x) = A & # 178;
3^(1-x)=3a
So a & # 178; - 6a-27 = 0
(a-9)(a+3)=0
a=3^(-x)>0
So 3 ^ (- x) = 9 = 3 & # 178;
-x=2
x=-2

Solution equation: X * 1 / 3 * 4 / 9 = 1 / 27

X*1/3*4/9=1/27
4*X/27=1/27
4X=1
X=1/4

Nine out of 64 times eight out of 27 requires a simple algorithm and detailed process

9/64*8/27=1/8*1/3=1/24