4+6+...+20+1-3-5-...-19= 199+299+399+499+599+5= 99999x22222+33333x33334= 591x482+118=

4+6+...+20+1-3-5-...-19= 199+299+399+499+599+5= 99999x22222+33333x33334= 591x482+118=


199+199+100+199+200+199+300+199+400+5
=(199×5+5)+(100+200+300+400)
=(199+1)×5+1000
=1000+1000
(199+1)+(299+1)+(399+1)+(499+1)+(599+1)
33333X3X22222+33333X33334
=33333X(3×22222+33334)
=33333X(66666+33334)
=33333X100000
591X482+600-482
=591X482-482+600
=590x482+600
=(600-10)X482+600
=600X482-10X482+600
=600X483-4820
=289800-4820
591X482+118
=591X(600-118)+118
=591X600-591X118+118
=591X600-590X118
=591×600-(600-10)X118
=591X600-600X118+118×10
=(591-118)x600+1180
=473x600+1180
=283800+1180



Kindergarten children are divided into five pears, five more than two pears, three more than two pears. How many pears are there at least?


Every time there are more than two, which means that the number is a multiple of 5 plus 2, which is also a multiple of 3 plus 2. That is to say, the number is a common multiple of 3 and 5 plus 2. Since the question is at least how many, it is the least common multiple of 3 and 5 plus 2, and the answer is 17



56000÷1000...0X300...0
1000 0 999 0
I can read it!


56000÷1000...0X300...0
1000 0 999 0
1000-999=1di xiao
It's 56000 △ 10 * 3 = 16800



The title is like this: 56000 * 1000... 0x300... 0
1000 0 999 0
Yes, please hurry up and wait!
Wrong. The title is 56000 △ 1000... 0x300... 0
1000 0 999 0
I'm so sorry, because it's helping others!


=16800000000 (2002)