X36 divided by 58, if the quotient is one digit, what is the maximum x? If the quotient is two digits, what is the minimum x

X36 divided by 58, if the quotient is one digit, what is the maximum x? If the quotient is two digits, what is the minimum x

Quotient is one digit, if ten is not enough, then X3

Simple application of factorization (23 12:14:38)
1.    x2-6x=-9
2.   (x+2)2=(2x+1)2
3.   9(x+3)2=(2x-5)2
If A2 + A-3 = 0, find the value of A4 + 2a3-a-1
 

1. X2-6x = - 9 x ^ 2-6x + 9 = 0 (x-3) ^ 2 = 0x = 32. (x + 2) 2 = (2x + 1) 2 [(x + 2) + (2x + 1)] [(x + 2) - (2x + 1)] = 0 (3x + 3) (- x + 1) = 03 (x + 1) (1-x) = 0x1 = - 1, X2 = 13.9 (x + 3) 2 = (2x-5) 2 [3 (x + 3) + (2x-5)] [3 (x + 3) - (2x-5)] = 0 (5x + 4) (x + 14) = 0x1 = - 4 / 5, X2 = - 144