17 * 23-23 * 79 (simple calculation)

17 * 23-23 * 79 (simple calculation)

17*23-23*79
=23*（17-79）
=23*（-62）
=-1426 .

027 × 9.9 + 0.27,

[-|98|+76+(-87)]*23[56+(-75)-(7)]-(8+4+3)
5+21*8/2-6-59
68/21-8-11*8+61
-2/9-7/9-56
4.6-(-3/4+1.6-4-3/4)
1/2+3+5/6-7/12
[2/3-4-1/4*(-0.4)]/1/3+2
22+(-4)+(-2)+4*3
-2*8-8*1/2+8/1/8
(2/3+1/2)/(-1/12)*(-12)
(-28)/(-6+4)+(-1)
2/(-2)+0/7-(-8)*(-2)
(1/4-5/6+1/3+2/3)/1/2
18-6/(-3)*(-2)
(5+3/8*8/30/(-2)-3
(-84)/2*(-3)/(-6)
1/2*(-4/15)/2/3
-3x+2y-5x-7y
(1) Write - 2 - (+ 3) - (- 5) + (- 4) + (+ 3) in the form of omitting the sum of brackets
A．-2-3-5-4+3 B．-2+3+5-4+3
C．-2-3+5-4+3 D．-2-3-5+4+3
(2) The correct result of (- 5) - (+ 3) + (- 9) - (- 7) + is ()
A．-10 B．-9 C．8 D．-23
(3) The algebraic sums of - 7, - 12, + 2 are smaller than the sum of their absolute values ()
A．-38 B．-4 C．4 D．38
(4) If + (B + 3) 2 = 0, then the value of B-A - is ()
A．-4 B．-2 C．-1 D．1
(5) The following statement is correct ()
A. Subtracting two negative numbers is equal to subtracting the absolute value
B. The difference between two negative numbers must be greater than zero
C. Positive minus negative is actually the algebraic sum of two positive numbers
D. Negative minus positive equals the absolute value of negative plus positive
(6) Formula - 3-5 cannot be read as ()
A. The difference between - 3 and 5 B. the sum of - 3 and - 5
C. The difference between - 3 and - 5 d. - 3 minus 5
2. Fill in the blanks: (4 ′× 4 = 16 ′)
（1）-4+7-9=- - + ；
（2）6-11+4+2=- + - + ；
（3）（-5）+（+8）-（+2）-（-3）= + - + ；
（4）5-（-3 ）-（+7）-2 =5+ - - + - .
3. Write the following forms in the form of sum with brackets omitted, and give two ways to read them: (8 ′× 2 = 16 ′)
（1）（-21）+（+16）-（-13）-（+7）+（-6）；
（2）-2 -（- ）+（-0.5）+(+2)-(+ )-2.
4. Calculation (6 ′× 4 = 24 ′)
(1)-1+2-3+4-5+6-7;
(2)-50-28+(-24)-(-22);
(3)-19.8-(-20.3)-(+20.2)-10.8;
(4)0.25- +(-1 )-(+3 ).
5. When x = - 3.7, y = - 1.8, z = - 1.5, find the value of the following algebraic formula (5 ′× 4 = 20 ′)
(1)x+y-z; (2)-x-y+z; (3)-x+y+z; (4)x-y-z.
On the first day, a water conservancy survey team walked 5 kilometers upstream, 5 kilometers upstream on the second day, 4 kilometers downstream on the third day, and 4.5 kilometers downstream on the fourth day. Where is the starting point of the survey team? How many kilometers apart?
6. The order of mixed operation of rational numbers is: calculate first, then, and finally. If there is, calculate first
11、8-4÷(-2)； 12、-9+5×(-6)-12÷(-6)
14、-1-〔1-(1-0.6÷3)〕×〔2-(-3)×(-4)〕；
20、0÷(-4)-42-(-8)÷(-1)3；
21、-32-(-3) 2-(-3)3+(-1)6；
24、3×(-2)2+(-2×3)2+(-2+3)2；
34、(-12)÷4×(-6)÷2；
(
36、(-12)÷4×(-6)÷2；
48. Given that a = 3, the opposite number of B is - 5, find the value of a-b
49. At that time, find the value of (2k2-4k-1) / (K2 + K + 1)
50, known a & gt; 0, AB & lt; 0, simplified A-B + 4 - b-a-3
There are a lot of them in the library

Simple calculation of recurrence equation: (1) 9.81x9.8 (2) 0.027 + 9.9x0.27 (3) 13.4-0.4x3

（1）9.81X9.8
=9.81×（10-0.2）
=98.1-1.962
=96.138
（2）0.027+9.9X0.27
=0.027+99×0.027
=0.027×（1+99）
=0.027×100
=2.7
（3）13.4-0.4X3
=13.4-1.2
=12.2

How to calculate 0.027 times 9.9 times 0.27

0, 27x0, 27x0, 99

Simple calculation. 0.027 + 9.9x0.27

(99+1)×0.027

A divided by B is equal to 52. What is the minimum of 5B?

The divisor of 6 must be larger than the remainder, so the smallest natural number larger than 5 is 6

What is the sum of 5 divided by B and a

5÷(b+a )

(a + b) Λ 5 divided by (- a-b) Λ 2 divided by (a + b)

Equal to (a + b) &;

Five eighths divided by two fifths = five eighths x () = ()
How did you get here?

Five eighths divided by two fifths = five eighths x (5 / 2) = (25 / 16)
To divide by a number is to multiply by the reciprocal of a number?
5 / 8 divided by 2 / 5 = 5 / 8 × 5 / 2 = 25 / 16

(1-1/80)*(1-1/79)*(1-1/78）*…… *（1-1/51）=（ ）
Why is the answer 7 / 10,

(1-1/80)*(1-1/79)*(1-1/78）*…… *(1-1 / 51) = (79 / 80) * (78 / 79) * (77 / 78) *. * (50 / 51) = 50 / 80 = 5 / 8