If 0.3mol electron is transferred, how many grams of aluminum can be obtained theoretically? How many moles of alumina do you need?

Suppose that the formation of metallic aluminum is x g and Y mole of alumina is needed, then 2mol Al 2O 3 ～～～ 4Al ～～ 12mol electron 2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 108G & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 3, that is: 2Y = 108x = 120.3x = 2.7gy = 0.05mol A: theoretically, 2.7g of aluminum can be obtained, and 0.05mol of alumina is needed

When 1mol of a gaseous hydrocarbon is completely burned to produce 3mol of carbon dioxide and 2mol of water, the molecular formula of the hydrocarbon is?

A: the molecular formula of this hydrocarbon is c3h4. The substance is hydrocarbon, so it contains only two elements. Let the chemical formula be CxHy. According to the chemical formula, 1mol of this hydrocarbon is completely burned to produce xmol of carbon dioxide and Y / 2mol of water. So x = 3, Y / 2 = 2. Get y = 4. So the simplest formula of this hydrocarbon is c3h4

1 the same amount of Na + Oh_ F - has the same proton number 2, neutron number 4 and mass
What is the ion number of Al 2 (so 4) 3 in 20.5mol?
The amount of CO2 with the same number of electrons in 0.11 mol sulfuric acid and 0.3 mol sulfuric acid is a 0.025 b0.05 c0.22 d0.25

1 (2) are all 10 Electron particles
2.1 mol of Al, 1.5 mol of sulfate, 2.5 mol
The electron number of 30.11 mol sulfuric acid is 5.51 mol CO2, so it is 0.25

Simple calculation of 14.45-7.25 + 5.55-2.75

14.45-7.25+5.55-2.75
=14.45+5.55-（7.25+2.75）
=20-10
=10

If 0.3mol electron is transferred, how many grams of aluminum can be obtained theoretically? How many moles of alumina do you need?