For a bottle of alcohol, pour out two-thirds and 20 grams at the first time, then pour back 35 grams, and pour out 50% of it at the second time. At this time, there is 45 in the bottle, how much is the original

For a bottle of alcohol, pour out two-thirds and 20 grams at the first time, then pour back 35 grams, and pour out 50% of it at the second time. At this time, there is 45 in the bottle, how much is the original

With X gram
（x/3-20+35）/2=45
x/3+15=90
x/3=75
x=225

A bottle of alcohol, the first pour out two-thirds and 20 grams, the second pour out is a quarter of the first, there are 35 grams of alcohol in the bottle, how much alcohol is there

Let the original alcohol be x G
2/3*X+20+1/4(2/3*X+20)+35=X
The results of solving linear equation with one variable
X=360
A: there was 360 grams of alcohol