2,4,3,6,5, (), (), 18,17. What's the rule

2,4,3,6,5, (), (), 18,17. What's the rule

2 times 2 and then subtract one, get 3 times 2 and then subtract one, get 5 and then multiply 2, get 10 is bracket 1
Minus one is nine
2,4,3,6,5,（10）,（9）,18,17

17 of 18 - (1 of 12 + 1 of 6)

17 of 18 - (1 of 12 + 1 of 6)
=17 / 18-3 / 12
=17 / 18-1 / 4
=34 out of 36-9 out of 36
=25 out of 36

((5 / 18) + (4 / 9) + (7 / 12)) * 36 simple formula 6x + 0.5 × 7 = 94.7 to find the unknown x

[(5/18)+(4/9)+(7/12)]×36
=(5/18)×36+(4/9)×36+(7/12)×36
=10+16+21
=47
6x+0.5×7=94.7
6x+3.5=94.7
6x=94.7-3.5
6x=91.2
x=15.2

(7-6 / 9 + 3 / 18) × 18-1.45 × 6 + 3.95 × 6

(7-6 / 9 + 3 / 18) × 18-1.45 × 6 + 3.95 × 6
=7/9x18-5/6x18+3/18x18+(3.95-1.45)x6
=14-15+3+2.5x6
=2+15
=17
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There are several alcohol solutions with 36% alcohol content. After adding a certain amount of water, dilute them to a solution with 30% alcohol content. If the solution is diluted to 24%, how many times of the water added last time?

Assuming that the 36% alcohol solution is 100 g, then the alcohol content is 100 × 36% = 36 (g); 36 △ 30% - 100 = 20 (g); (36 △ 24% - 100-20) △ 20, = 30 △ 20, = 1.5 times; a: the amount of water added is 1.5 times of that added last time

Dissolve 18 kg of salt in 42 kg of water to make a solution
10 kg of salt is dissolved in 90 kg of water to form solution B. now 100 kg of solution with 18% salt content is prepared. How many kg of solution a and B are needed

Mass fraction of a solution = 18 / (18 + 42) = 30%
Mass fraction of B solution = 10 / (10 + 90) = 10%
Suppose the mass of solution a is x, then the mass of solution B is 100-x
From the theme
30%x+10%(100-x)=100g*18%
We can get x = 40g
The mass of solution a is 40g and that of solution B is 60g
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Dissolve 2kg of salt in 18kg of water to form solution a, dissolve 1kg of salt in 3kg of water to form solution B, and now prepare 10kg of 13% salt solution
How many kilos of a and B solution are needed

Concentration of a solution = 2 ÷ (2 + 18) = 10%
Concentration of B solution = 1 ÷ (1 + 3) = 25%
Let a solution x kg and B solution 10-x kg
10%x+25%(10-x)=13%
The solution is x = 8 kg
Solution a 8kg, solution B 2kg

Dissolve 12 kg sugar in 18 kg water to form solution a, and 9 kg sugar in 13.5 kg water to form solution B,
What is the concentration of the new solution?

Mass of solute = 12 + 9 = 21kg
Mass of solution = 12 + 18 + 9 + 13.5 = 42.5
Concentration of solution = 21 / 42.5 = 49.4%

Two thousand grams of salt are dissolved in 18 kg of water to form a, and one kilogram of water is dissolved in 3 kg of water to form B. now, how many kg of a and B are needed to form a 13% salt solution?

Concentration of a solution = 2 ÷ (2 + 18) = 10%
Concentration of B solution = 1 ÷ (1 + 3) = 25%
Let a solution x kg and B solution 10-x kg
10%x+25%(10-x)=13%
The solution is x = 8 kg
Solution a 8kg, solution B 2kg

Dissolve 12kg salt in 18kg water to make a solution, 9kg salt in 3kg water to make B solution, 1.5% salt and 1.5% water to make 14kg solution, 1.5% salt and 1.5% water to make B solution
How much is the solution kg

Let a be XKG and B be 14-xkg
x*[12/(12+18)]+(14-x)*[9/(9+3)]=14*(1/2)
x/5+(14-x)*(3/4)=7
x/5-3x/4=7-10.5
-11x/20=-3.5
x=70/11≈6.4kg
That is to say, a 6.4kg, B 14-6.4 = 7.6kg