1×2×3×… X 100, the end of the product of these 100 numbers has______ A continuous zero

1×2×3×… X 100, the end of the product of these 100 numbers has______ A continuous zero

25 is the square of 5, which contains two prime factors 5. Here there is one more 5. From 1 to 30, although only 20 of the 100 factors are multiples of 5, they contain 24 prime factors 5. So there are 24 zeros at the end of the product. There are 100 ／ 5 = 20 multiples of 5. There are 100 ／ 25 = 4 multiples of 25, there are 20 + 4 = 24. So the answer is: 24

There should be several zeros at the end of the product of 1 times 2 times 3 times 4 times 99 times 100

10=5*2
The factor of 5 is (100 / 5) + (100 / 25) = 24
The factor of 2 is much more than that of 5
So there are 24 factors of 10
There are 24 zeros at the end of this formula

What is the product of 100 - 2 times 99 - 2 times 2

-The 101st power of 2

Multiply 1 × 2 × 3 to 30, and there are several zeros at the end of the product

What they said is wrong. It depends on how many 2 and 5, the product of 2 and 5 is the number with zero at the end. 5 must be less than 2. So to see how many 5 are, is to find how many zeros there are. From 1 to 30, 5, 10, 15, 20, 25 and 30 are multiples of 5. 25 is the square of 5, so there are 7 zeros

-A simple method to calculate 99 times 999

-99 times 999
=-99×(1000-1)
=-99000+99
=-98901;
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Is there a simple method for 999 × 1999

999×1999
=(1000-1)×1999
=1999000-1999
=1999000-2000+1
=1997001

1999 + 999 + 999 is a simple method

1999+999+999
=2000-1+1000-1+1000-1
=4000-3
=3997

How to calculate the recurrence equation of 999 times 999 with a simple method

999 times 999
=(1000-1)×(1000-1)
=1000²-2×1000+1
=1000000-2000+1
=998001

Simple 0.999 × 1.3-0.111 × 2.7

0.999*1.3-0.111*2.7
=0.999*1.3-0.111*9*0.3
=0.999*1.3-0.999*0.3
=0.999*(1.3-0.3)
=0.999*1
=0.999

Ingenious calculation: 0.888 * 125 * 73 + 999 * 3 = solution equation (5.2-3x / 2 + 2) / 3 = 0.53.5 (12 + 2x) = 59-1.5x
(1 minute)

0.888*125*73+999*3
=0.111*(8*125)*73+111*9*3
=0.111*1000*73+111*27
=111*(73+27)
=11100
7.2-1.5x=1.5
x=(7.2-1.5)/1.5=3.8
3.5*12+3.5*2*x=59-1.5x
8.5x=59-42
x=2