Simple calculation: 34 * 36 + 68 * 32

Simple calculation: 34 * 36 + 68 * 32

34*36+68*32
=34*36+34*(2*32)
=34*(36+64)
=34*100
=3400

Simple calculation: 68 × 32-784 △ 56=
3500÷42=

68×32-784÷56
= (70-2)*(30+2) - (7*112)/(7*8)
= 2100 + 2(70-30) - 4 - 112/8
= 2100 + 80 - 4 - 14
= 2180 - 18
= 2162

How to calculate (2.68-0.48) × 6.5

(2.68-0.48)×6.5
=2.2×6.5
=2×6.5+0.2×6.5
=13+1.3
=14.3

Simple calculation of 67 / (67 + 68 / 67)

=67/[67×(1+1/68)]
=1/(1+1/68)
=1/(69/68)
=68/69

The sum of the natural numbers ABCD is 90. Given that a plus 2, B minus 2, c times 2, D divided by 2, the result is the same, then B is equal to 2
The sum of natural numbers ABCD is 90. Given a plus 2, B minus 2, c times 2, D divided by 2, the result is the same, then what is B equal to

It can be seen from the meaning of the title:
A＋2=B-2=2C=D/2
∴A=B-4
C=(B-2)/2
D=2(B-2)
∵A+B+C+D=90
∴(B-4)+B+(B-2)/2+2(B-2)=90
B=22
A: B equals 22
Glad to answer for you

A four digit ABCD, ABCD represents a number, ABCD divided by a, B, divided by 10 * C + D is equal to 8, find the number of the four digits

1000A+100B+10C+D=8AB(10C+D)
(1000A+100B)/(10C+D)+1=8AB
100(10A+B)=K(10C+D)
Let 10A + B = K (10c + D)
100k + 1 = 8ab, odd on the left and even on the right
So 100 = K (10c + D)
Because 100 = 2 * 50 = 4 * 25 = 5 * 20 = 10 * 10
And K (10a + b) + 1 = 8ab, so K cannot be even, it can only be 5
So C = 2, d = 0
50A+5B+1=8AB
5B+1=A(8B-50)
(5B+1)/[2(4B-25)]=A
B cannot be even and a > 0
So b > 25 / 4, B = 7,9
When B = 7, a = 6
So the number is 6720

It is known that a times 120 percent = three fourths times b = C divided by 0.15 = D divided by three-thirds [a, B, C, D are not 0], and the four numbers of a, B, C, D are increased from large to small

Suppose the results are all 1 d = 2 / 3 = 3 divided by 2 = 1.5 C = 1 divided by 0.15 B = 3 / 4 reciprocal is 4 / 3 = 4 divided by 3 = 0.75 a = 0.12 percent 120 is equal to 0.12 so: D is greater than B is greater than C is greater than a

There are four natural numbers a, B, C, D, the sum of which is not more than 400, and a divided by B quotient 5 more than 5; a divided by C quotient 6 more than 6; a divided by D quotient 7 more than 7. What is the sum of these four natural numbers______ ．

The quotient of a divided by B is more than 5, so a = 5B + 5, so a is a multiple of 5; similarly, the quotient of a divided by C is more than 6, and the quotient of a divided by D is 7 divided by 7, then a is a multiple of 6 and 7. The least common multiple of 5, 6 and 7 is 5 × 6 × 7 = 210, and not more than 400, then a < 400, and 2 times of 210 is more than 400, so a = 210, B = (210-5) △ 5 = 4

There are four natural numbers a, B, C, D, the sum of which is not more than 400, and a divided by B quotient 5 more than 5; a divided by C quotient 6 more than 6; a divided by D quotient 7 more than 7. What is the sum of these four natural numbers______ ．

A divided by B quotient is more than 5, so a = 5B + 5, so a is a multiple of 5; similarly, a divided by C quotient is more than 6, a divided by D quotient is 7 divided by 7, then a is a multiple of 6 and 7. The least common multiple of 5, 6, 7 is 5 × 6 × 7 = 210, and not more than 400, then a < 400, and 2 times of 210 is more than 400, so a = 210, B = (210-5) △ 5 = 41, C = (210-6) △ 6 = 34, d = (210-7) △ 7 = 29. So a + B + C + D = 314 The sum of natural numbers is 314

Given 5a-2b / a = 1 / 2, find the value of B / A

-2b/a=1/2-5a
2b/a=5a-1/2
b/a=2.5a-1/4