How to solve the equation when (x + 24) / (x + 54) = 1 / 2?

How to solve the equation when (x + 24) / (x + 54) = 1 / 2?

（x+24）/(x+54)=1/2
Multiply both sides by X + 54
We get x + 24 = 1 / 2 (x + 54)
x+24=x/2+27
x-x/2=27-24
x/2=3
x=6
Do not understand, welcome to ask

X + X + X + y + y = 54, x + X + y + y = 46, then what are x and y?

3x+2y=54 (1)
2x+2y=46 (2)
(1)-(2) x=8
y=15

9 (X-6) = 54 equations

9(x－6)＝54
x-6=54÷9
x-6=6
x=6+6
x=12
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If x + X + X + y + y = 54, x + X + y + solves y = 46, then what are x and y? Solve the equation

x+x+x+y+y=54,x+x+y+y=46
3x + 2Y = 54 one
2X + 2Y = 46 two
Solution: 3x-2x + [2y-2y] = 54-46
X=8
Substituting 1: 3 * 8 + 2Y = 54, y = 15
X=8 Y=15