If the equation 1 + 2K divided by 9 - (the square of x = k divided by x-3) has an increasing root, then k =?

If the equation 1 + 2K divided by 9 - (the square of x = k divided by x-3) has an increasing root, then k =?

(1+2k)/(9-x^2)=k/(x-3)
1+2k=-k(x+3)
kx+5k+1=0
The increasing root is x = 3, or x = - 3
When x = 3, k = - 1 / 8
When x = - 3, k = - 1 / 2
K = - 1 / 8 or - 1 / 2

Equation x divided by 2 + a divided by 3 is the same as equation X-6 divided by 2 = - 6

First, we solve the second equation: (X-6) / 2 = - 6, X-6 = - 12, x = - 6
We take x = - 6 into the first equation and get X / 2 + A / 3 = - 3 + A / 3 = - 6, a / 3 = - 3, a = - 9
In fact, you haven't finished the first equation, so no one answered. I assume that it is equal to - 6. If not, you can bring the number in yourself~

Equation (x-2100) divided by = 0.25
(x-2100) divided by x = 0.25

There is something wrong with your equation. What is the division after division? You write it down, I can do it
Is x missing? Is the equation: (x-2100) / x = 0.25
If so, the answer is: 2800

75% divided by x = 0

0.25x=0.75
x=3