Curve: X & sup3; - 3x & sup2; + 2x straight line, y = KX, and the tangent between the straight line and the curve and the point (x0, Y0) (x0 ≠ 0), find the equation of the straight line and the tangent point coordinates

Curve: X & sup3; - 3x & sup2; + 2x straight line, y = KX, and the tangent between the straight line and the curve and the point (x0, Y0) (x0 ≠ 0), find the equation of the straight line and the tangent point coordinates

Let f (x) ∵ go through point (x0, Y0) ∵ Y0 = k * x0 = f (x0), simplify k = x0 ^ 2 - 3 x0 + 2 ∵ tangent ∵ f '(x0) = 3 x0 ^ 2 - 6 x0 + 2 = k ∵ x0 ^ 2 - 3 X0 + 2 = 3 x0 ^ 2 - 6 x0 + 2, and get x0 = 0 (rounding off) or x0 = 3 / 2

In P (x0, Y0) point, 0 means when x and y are equal to zero,
ax+by+c=0 x0,y0
|ax0+by0+c|/√(a^2+b^2)
Here 0 means x, the exponent of Y is 0 or what?
In the second formula, it means to substitute x0, Y0 into X,

0 is the subscript of X, which means that the point (x, y) does not participate in the operation. It can also be expressed as (x1, Y1) and so on