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Given that ab = 1, CD = 2, the circumscribed sphere radius r = 3 in the tetrahedral ABCD, the maximum volume of the tetrahedral ABCD can be obtained
The data of this question is not very good, and it doesn't make much sense to do it. We can get V less than or equal to (1 / 3) * (√ 5 + 2 √ 2)
Why is the sixth power of 2 + the sixth power of 2 equal to the seventh power of 2
Why is the sixth power of 2 + the sixth power of 2 = the seventh power of 2
The sixth power of 2 + the sixth power of 2
=The sixth power of 2 * 2
=1 power of 2 * 6 power of 2
=The 7th power of 2
What is 4.91 times 10 to the sixth power
The sixth power of 10 is six 10 times = 1000000, and then multiplied by 4.91 = 4910000
Find all prime numbers so that the third power of P minus the seventh power of Q equals P minus Q
P ^ 3-q ^ 7 = P-qP * (P ^ 2-1) = Q * (Q ^ 6-1) because both P and Q are prime numbers, P | Q ^ 6-1q | (P + 1) (p-1) P | (Q + 1) * (Q ^ 2-Q + 1) * (Q ^ 2 + Q-1) obviously, in Q | (P + 1) * (p-1), if Q | P + 1 and Q | P-1 are satisfied at the same time, then q = 2, but it is not consistent with the original question
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- 4. In rectangular ABCD, the diagonal lines AC and BD intersect at O, ∠ AOD = 120 °, BC = 3cm under the root sign. Calculate the length of AC and the area of rectangular ABCD
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- 9. The circumference of rectangle ABCD is 28cm, its two diagonals intersect at point O, the circumference of △ AOB is 2cm shorter than that of △ BOC, then AB = (), BC = ()
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- 17. As shown in the figure, ab | DC, ad | BC, points E and F are on AB and DC respectively, and be = DF, AF = CE
- 18. As shown in the figure, AC ⊥ BC, ad ⊥ BD, ad = BC, CE ⊥ AB, DF ⊥ AB, perpendicular feet are e and f respectively, so, CE = DF?
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