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As shown in the figure, ab = CD, DF ⊥ AC in F, be ⊥ AC in E, DF = be, verification: AF = CE
It is proved that: ∵ DF ⊥ AC, be ⊥ AC, ∵ AEB = ∠ CFD = 90 ° in RT △ Abe and RT △ CDF, ab = cddf = be, ≌ RT △ Abe ≌ RT △ CDF (HL), ∥ AE = CF, ∥ ae-ef = cf-ef, that is AF = CE
As shown in the figure, we know ab ‖ CD, AF = CE, ∠ B = D, and prove the relationship between be and DF
It is proved that: ∵ ab ∥ CD, be = DF, ∵ a = ∠ C, and ∵ AF = CE, ∵ AF + Fe = CE + Fe, that is AE = cf. in △ Abe and △ CDF, ≌ a = ≌ C (proved) ∩ B = ∩ D (known), AE = CF (proved), ≌ Abe ≌ CDF (AAS), ≌ be = DF
The angle AB is equal to CD, AF is equal to CE, be is perpendicular to e, DF is perpendicular to F
Prove that triangle? And what is the angle AB? Supplement: because AF equals CE, so AF + CF = AC, CE + AE = AC, so AE = CF; and because AB = CD, so all triangle Abe equals CDF
Known: as shown in the figure, points B, e, C, f are on the same line, ab = De, AC = DF, be = CF
It is proved that: ∵ be = CF, ∵ BC = EF, ab = De, AC = DF, ≌ ABC ≌ def, ≌ B = ≌ def, ∥ ab ∥ de (the same angle, two lines parallel)
RELATED INFORMATIONS
- 1. Known: as shown in the figure, points B, e, C, f are on the same line, ab = De, AC = DF, be = CF
- 2. Known: as shown in the figure, points B, e, C, f are on the same line, ab = De, AC = DF, be = CF
- 3. As shown in the figure, in △ ABC, D is the point on AB, DF intersects AC at e, de = Fe, AE = CE, what is the positional relationship between AB and CF? Prove your conclusion
- 4. It is known that in diamond ABCD, e and F are points on AB and ad respectively, and AE = AF. verification: CE = CF
- 5. Given that ab = 1, CD = 2, the circumscribed sphere radius r = 3 in the tetrahedral ABCD, the maximum volume of the tetrahedral ABCD can be obtained
- 6. M ^ 2 + M-1 = 0, find the value of m ^ 3 + 2m ^ 2 + 2012
- 7. If the solution set of inequality | x2-8x + a | ≤ x-4 is [4,5], then the value of real number a is equal to______ ．
- 8. In triangle ABC, Pb is vertical to AB, PR is vertical to BC, PS is vertical to AC, and PQ = 6, PR = 8, PS = 10 Q. R and s are on three sides
- 9. In rectangular ABCD, the diagonal lines AC and BD intersect at O, ∠ AOD = 120 °, BC = 3cm under the root sign. Calculate the length of AC and the area of rectangular ABCD
- 10. The two diagonals of rectangle ABCD intersect at point O. given that the angle AOD is equal to 120 ° and ab is equal to 2.5cm, find the length of the diagonal of rectangle?
- 11. It is known that: as shown in the figure, AC bisects ∠ bad, CE ⊥ AB in E & nbsp; CF ⊥ ad in F, and BC = DC
- 12. As shown in the figure, ab | DC, ad | BC, points E and F are on AB and DC respectively, and be = DF, AF = CE
- 13. As shown in the figure, AC ⊥ BC, ad ⊥ BD, ad = BC, CE ⊥ AB, DF ⊥ AB, perpendicular feet are e and f respectively, so, CE = DF?
- 14. The vertical line CE is drawn from the vertex C of rectangle ABCD to the diagonal BD, and the perpendicular foot is e. if CE is divided into two angles with ∠ C being 1:5, then ∠ ace=
- 15. It is known that in trapezoid ABCD, ab ∥ CD, ad = DC = BC = 4 ∠ DCB = 120 ° CE ⊥ AB, the area of AC ⊥ BC and trapezoid is calculated
- 16. Known: as shown in the figure, EF is the median line of trapezoidal ABCD, AF bisector angle DAB verification: ad = 2ef There is no picture
- 17. As shown in the figure: AE is the bisector of ∠ BAC in square ABCD, AE intersects BD and BC at f and e respectively, AC and BD intersect at O, verification: of = 12ce
- 18. As shown in the figure, in ▱ ABCD, if the bisector AE of ∠ bad intersects BC at e, ad = 6, EC = 2, then the length of CD=______ ．
- 19. Find the normal vector of the plane passing through points a (0,0,0), B (1,4,0), C (0,2,0)
- 20. It is known that the vertex of the parabola is at the origin and the focus is the focus of the hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1