In order to get the image of y = sin2x, we only need to set the image of y = - cos2x | Math enthusiast | Mathematical art

In order to get the image of y = sin2x, we only need to set the image of y = - cos2x

This problem can be done by drawing function image, but it is troublesome
The induction formula can be used because - cos (2x) = sin (2x pi / 2) = sin (2 (x-pi / 4))
So to get y = sin2x, just shift pi / 4 to the left~
Welcome to ask~

To get the image of y = sin2x, we just need to explain the image of y = cos2x in detail

y=cos2x=cos(-2x)
=sin(π/2+2x)
=sin[2(x+π/4)]
To get an image of y = sin2x
Just shift the image of y = cos2x π / 4 units to the right

The range of function y = □ (1 / 2) sin2x + 4sin ^ 2 x, X ∈ R is

Reduction y = (1 / 2) sin2x + 4sin ^ 2 x = (1 / 2) sin2x + 2 (1-cos (2x)) = 2 + (1 / 2) sin2x-2cos (2x)
=2+(17^0.5/2)sin(2x+O),
De maximum

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