Given points a (radical 3, - 4), B (- 3, radical 3,8), if | PA | = | Pb |, prove that the moving point P is on a straight line 2. Find the intercept and inclination angle of the straight line in 1 on x-axis and y-axis

Given points a (radical 3, - 4), B (- 3, radical 3,8), if | PA | = | Pb |, prove that the moving point P is on a straight line 2. Find the intercept and inclination angle of the straight line in 1 on x-axis and y-axis

1. P (x, y) PA & sup2; = Pb & sup2; so (x - √ 3) & sup2; + (y + 4) & sup2; = (x + √ 3) & sup2; + (Y-8) & sup2; X & sup2; - 2 √ 3x + 3 + Y & sup2; + 8y + 16 = x & sup2; + 2 √ 3x + 3 + Y & sup2; - 16y + 64 √ 3x-6y + 48 = 0, so it is a straight line 2, y = (√ 3 / 6) x + 8y = 0, x = 16 √ 3x = 0, y = 8

It is known that the total area of a cone whose generatrix is 3cm is equal to the area of a circle whose radius is 2cm, and the side area of the cone is calculated

Let the radius of the bottom of the cone be x cm
The side area of the cone is 3 π x square centimeter, and the bottom area is π X & # 178; square centimeter
A circle with a radius of 2 cm has an area of 4 π square centimeter
So 3 π x + π X & # 178; = 4 π
X²+3X-4=0
（X-1）（X+3）=0
X1 = 1, X2 = - 3 (rounding off)
The bottom radius of the cone is 1 and the side area is 3 π square centimeter

Let m be the moving point on ⊙ C: (x + 1) 2 + y2 = 4, PM be the tangent of ⊙ C, and | PM | = 1, then the trajectory equation of point P is ()
A. （x+1）2+y2=25B. （x+1）2+y2=5C. x2+（y+1）2=25D. （x-1）2+y2=5

As shown in the figure, ∵ C: (x + 1) 2 + y2 = 4 center C (- 1, 0), radius r = 2. M is the moving point on ⊙ C: (x + 1) 2 + y2 = 4, PM is the tangent of ⊙ C, and | PM | = 1, connecting PC, then ∵ PMC is RT △ and | PC | = | PM | 2 + | MC | 2 = 12 + 22 = 5

The generatrix of a cone is 3cm long, and its total area is equal to the area of a circle with a radius of 2cm
The generatrix of a cone is 3cm long, and its total area is equal to the area of a circle with a radius of 2cm

Let the apex angle of the expanded cone sector be a, the circumference of the bottom circle be 2 π RA / (2 π) = RA = 3A, the radius of the bottom circle be 2 π r = 3A, r = 3A / (2 π), the bottom area be π R ^ 2 = 9A ^ 2 / (4 π), the side area of the cone be π R ^ 2A / (2 π) = ar ^ 2 / 2 = 9A / 2, and the small circle area be 4 π, then 4 π = 9A ^ 2 / (4 π) + 9A / 2

In the isosceles trapezoid ABCD, AB / / CD, P is a point in the trapezoid and PC = PD, PA = Pb
Please answer,

Solution: because of isosceles trapezoid, ad = CB, ADC = angular CBD, PC = Pb, so isosceles triangle star PCD, that is, angle PDC = angular PCD, because angle ADC = angular CBD, so angle ADP = angular BCP, because ad = CB, PC = Pb, so triangle star DPA is equal to triangle CPB, so PA = Pb

A cylindrical plasticine, the bottom area is 12cm square, the height is 5cm, pinch it into a cone of the same height, how much is the bottom of the cone?
I'm in a hurry! Please answer quickly!

Yuxin g,
Rubber clay volume: 12 × 5 = 60 (cm3)
Cone bottom area: 60 × 3 △ 5 = 36 (square centimeter)

In p-abcd, CD ⊥ PD. The bottom surface ABCD is a right angle trapezoid, ad ∥ BC, ab ⊥ BC, ab = ad = Pb. The point E is on the edge PA
In p-abcd, CD ⊥ PD. The bottom surface of ABCD is a right angled trapezoid, ad ∥ BC, ab ⊥ BC, ab = ad = Pb = 3, point E is on the edge PA, and PE = 2EA
(1) Seeking BC length
(2) Finding the angle between PA and CD

Because Pb ⊥ surface ABCD, so Pb ⊥ CD and PD ⊥ CD intersect at point P, so CD ⊥ surface PBD line BD is in surface PBD, so CD ⊥ BD because ab ⊥ BC, bottom surface ABCD is right angle trapezoid, so ∠ ABC = ∠ DAB = 90 ° and because AB = ad = 3, so △ bad is isosceles straight angle triangle, ∠ abd = ∠

It is known that the ratio of the bottom area of a square measuring cup to that of a cylindrical measuring cup is 3:5, and the bottom radius of the cylindrical measuring cup is 5cm. Now we need to pour 0.785l of water into two empty cups. The water surface in the two cups is the same height. How many centimeters is the water surface in each cup? (thickness ignored)

Area of cylinder base = 5 × 5 × 3.14 = 78.5 square centimeter
Area of cube base = 78.5 △ 5 × 3 = 47.1 square centimeter
0.785 L = 785 CC
Height = 785 ÷ (78.5 + 47.1) = 6.25cm

A. B.c.d. how to find a point P to make PA = Pb = PC = PD?

Separately AB.BC.CD The perpendicular of. Da intersects at one point, which is p

The volume of a cone is 62.4 cubic centimeters, which is four times the volume of the other cone. If the height of the other cone is 2.5 centimeters, the bottom area of the cone is______ ．

3 × (62.4 ﹣ 4) ﹣ 2.5, = 3 × 15.6 ﹣ 2.5, = 46.8 ﹣ 2.5, = 18.72 (square centimeter); answer: the bottom area of this cone is 18.72 square centimeter. So the answer is: 18.72 square centimeter