It is known that the visual image of a square is a parallelogram, in which one side is 4 long, then the area of the square is () A. 16b. 64c. 16 or 64D. Cannot be determined

As shown in the figure: ① if the side of the parallelogram in the visual graph is a ′ B ′ = 4, then the side length of the original square is ab = a ′ B ′ = 4, so the area of the square is s = 42 = 16. ② if the side of the parallelogram in the visual graph is a ′ D ′ = 4, then the side length of the original square is ad = 2A ′ D ′ = 8, so the area product of the square is s = 82 = 64

It is known that the visual image of a square is a parallelogram, in which one side is 4 long, then the area of the square is 16 or 64. Why?

Let the square ABCD, AB as the bottom, be shared by the square and parallelogram,
Visual graph ABC'd ',

The areas of a parallelogram and a square are equal. It is known that the bottom of the parallelogram is 3.6 decimeters. Find the height of the parallelogram (the side length of the square is 6 decimeters)

6×6÷3.6=10dm
The height is 10 decimeters
Hope to adopt

A parallelogram with a bottom of 0.4m has the same area as a square with a side length of 0.36M. How many meters is the height of the parallelogram corresponding to the bottom?

0.36*0.36/0.4=0.324(m)

What is the area of a parallelogram with an upper base of 15 cm, a lower base of 10 cm and a height of 12 cm?
What's the formula

(15 + 10) * 12 / 2 = 150 square centimeter

Pull a rectangle 12 cm long and 6 cm wide into a parallelogram 10 cm high. The bottom of the parallelogram is cm and the area is square cm

Pull a rectangle 12 cm long and 6 cm wide into a parallelogram 10 cm high
The base of this parallelogram is 6cm and the area is 60cm
Note: after the rectangle is drawn into a parallelogram, the height becomes shorter, and the current height is 10, so the width can only be fixed as the bottom, and the original length can be moved

The length of two diagonals and one side of a parallelogram can be taken as ()
A. 6，6，6B. 6，4，3C. 6，4，6D. 3，4，5

As shown in the figure, let the two diagonals of the parallelogram be x, y; the side length be a, then 12x-12y < a < 12x + 12Y, and then judge according to this inequality: A, 3 + 3 + = 6; B, 3 + 2 > 3; C, 3 + 2 < 6; D, 1.5 + 2 < 5

In △ ABC, ab = 8, BC = 5, CA = 6. If you draw a parallelogram with two sides as edges and the other side as diagonals, the drawn parallelogram ()
A has the same size B has the same perimeter C has the same area D has the same shape

C is equal in area
All equal to twice the area of △ ABC

In the triangle ABC, ab = 8, BC = 5, AC = 6, draw parallelogram with two sides as sides and the other side as diagonal,
Parallelogram drawn
A. The same size
B. Equal girth
C. Equal area
D. Same shape

Taking 56 as the edge and 68 as the edge, the circumference must be different
The shape must be different
I just don't understand what the landlord means
Is the same size different from the same area?
The areas must be equal
Because the graph is congruent with the original triangle
I wish you success in your studies

In △ ABC, ab = 9, AC = 8, BC = 11, how many parallelograms can be drawn with two sides as sides and the third side as diagonal?

3 in total
Let's make CD ∥ AB through point C and BD ∥ AC through point B. the first one comes out
Let's make be ∥ AC through point B, and let's make AE ∥ BC through point a. the second one comes out
AF ∥ BC through point a, CF ∥ AB through point C. The third one comes out
Teach you the simplest method: make three parallel lines of three lines through three points. After the three lines intersect, three parallelograms will come out. At that time, just mark them with symbols

It is known that the visual image of a square is a parallelogram, in which one side is 4 long, then the area of the square is () A. 16b. 64c. 16 or 64D. Cannot be determined