It is known that ad is the middle line of triangle ABC. Try to find the size of AB + AC and 2ad

It is known that ad is the middle line of triangle ABC. Try to find the size of AB + AC and 2ad


A: ab + AC > 2ad
It is proved that extending ad makes de = ad, connecting be and CE
Because ad is the center line of triangle ABC
So BD = CD
Because ad = de
So the quadrilateral ABEC is a parallelogram
So AC = be
So in the triangle Abe
AB+BE>AE
That is ab + AC > 2ad



If the perimeter of a triangle is 10cm, one side is 3cm, and the other side is xcm, then the value range of X is


The perimeter of the triangle is 10cm, one side is 3cm, the other side is xcm, and the other side is 7-x
3+x>7-x,x>2
x-(7-x)



The base of isosceles triangle is 10cm long, and the value range of waist x is


  ∵2x>10
  ∴x>5
The range of waist x is x > 5cm



The length of two sides of a triangle is 8cm and 10cm respectively, and the length of the third side is xcm______ .


In a ∵ triangle, the sum of any two sides is greater than the third side, ∵ x ﹤ 8 + 10 = 18, ∵ the difference of any two sides is less than the third side, ∵ x ﹥ 10-8 = 2, ∵ X's range is 2 ∵ x ﹤ 18



The lengths of two sides of a triangle are 7cm and 11cm respectively. What is the value range of its perimeter l?


Range of third side C: 11-7



If the base of isosceles triangle is 10cm long, the range of waist length is? Please explain and answer in detail


> 5 cm
If the waist length is x cm (x > 0), the sum of any two sides is greater than the third side
x+x > 10…… (1)
10+x > x…… (2)
x+10 > x…… (3)
Where (2) and (3) are equivalent and hold for all real numbers
The solution (1) is: x > 5



If three sticks with the length of 4cm, 5cm and xcm form a triangle, then the value range of X is ()


The sum of any two sides of a triangle is greater than the third side, and the difference between any two sides of a triangle is less than the third side
So 5-4



If the base length of isosceles triangle is 5cm and the waist length is xcm, then the value range of X is


Any two sides of a triangle must be greater than the third side, and the inequality: x + x > 5 is obtained
∴x>2.5



The perimeter of a parallelogram is 48CM, and the heights of the two parallelogram are 7cm and 5cm respectively. What is the area of the parallelogram


Let X and y be the two sides respectively, and then we get the system of linear equations of two variables
x+y=48/2
7x = 5Y (equal area)
Figure it out for yourself



It is known that the perimeter of the parallelogram is 68, and the heights of the two adjacent sides are 8 and 9 respectively


Let the long side be a and the short side be B. the system of equations can be formulated as follows
2(a+b)=68
8a=9b
The area of parallelogram is 144 square centimeter