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When m is a value, the equation (m-2) x-mx + 2 = M-X is a quadratic equation of one variable about x? Write its quadratic term, coefficient of first term and constant term
The results show that (m-2 + 1) x-mx + 2-m = 0, the quadratic term is (m-2 + 1), the primary term is - m, and the constant term is 2-m
81（x-2）²=16,
81（x-2)²=16
﹙x－2﹚²＝16／81
x-2=±4／9
x=2±4／9
x=22／9,x=14／9
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16 (x + 2) & 178; - 81 = 0
16（x+2）²-81= 0
（x+2）²= 81/16
X + 2 = ± 9 / 4
X = 1 / 4 or x = - 17 / 4
How to solve 25 (x-1) & 178; = 16 (X-2) & 178?
25(x-1)²=16(x-2)²
(5x-5)²=(4x-8)²
(5x-5)²-(4x-8)²=0
（5x-5+4x-8）（5x-5-4x+8）=0
(9x-13)(x+3)=0
x1=13/9 x2=-3
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