100（1＋x）²＝121

100（1＋x）²＝121

100（1＋x）²＝121
The results are as follows
(1+x)^2==121/100
1 + x = = root (121 / 100)
Or 1 + x = = - radical (121 / 100)
The results are as follows
x1==11/10
Or x2 = = - 11 / 10

Given (x-1) &# 178; - 25 = 0, find the value of X

（x-1）²-25=0
（x-1）²=25
x-1=±5
So x = - 4, x = 6

Given: (x + 25) &# 178; + (y + 4) + √ (Z-4) = 0, find the value of √ XYZ

∵:(x+25)²+(y+4)+√(z—4)=0,
Then x + 25 = 0, y + 4 = 0, Z-4 = 0
x=-25 y=-4 z=4
∴√xyz=√[(-25)*(*4)*4]=√400=20

(x + 1) ² = 4 to find the value of X

(x+1)²=4
x+1=-2,x+1=2
x=-3,x=1