Given that the result of (x 2 + m x + n) (x + 1) does not contain x 2 term and X term, find the value of M, n

Given that the result of (x 2 + m x + n) (x + 1) does not contain x 2 term and X term, find the value of M, n

(x2 + MX + n) (x + 1) = X3 + (M + 1) x2 + (n + m) x + n. also ∵ the result does not contain the term of x2 and the term of X, ∵ m + 1 = 0 and N + M = 0. The solution is m = - 1, n = 1

If (x-3) (x-n) = x & # 178; + MX-15, then M = () n equals ()

(X-3)(X-N)
=x^2-(3+n)x+3n
=X²+MX-15
3+n=-m
3n=-15
n=-5
m=2

If x ^ 2 + MX-15 = (x + 3) (x + n), then the value of M is?
Known: A ^ m * a ^ n = a ^ 4, a ^ m / A ^ n = a ^ 6, then Mn =?

If X & sup2; + MX-15 = (x + 3) (x + n), then the value of M is? Expand the known equation to get X & sup2; + MX-15 = x & sup2; + (n + 3) x + 3N, then M = n + 33n = - 15, then m = - 2n = - 5, so m = - 2; known: A ^ m * a ^ n = a ^ 4, a ^ m / A ^ n = a ^ 6, then Mn =? From known, get a ^ (M + n) = a ^ 4, a ^ (m-n) = a ^ 6

Given X & # 179; - 16x & # 178; + mx-n divided by X & # 178; - 2x + 3, the remainder is - 18x + 15, try to find the value of M and n
In a hurry. Sit and wait~`·

The title is wrong