The smallest integer satisfying inequality 1.6 + 0.2x > 5 is

The smallest integer satisfying inequality 1.6 + 0.2x > 5 is

X is greater than 17, so the minimum is 17

System of inequalities 2x + 5 > - 1, X / 3

From 2x + 5 > - 1
Get x > - 3
By X / 3

Inequality of 3 (y + 1) > 4Y + 2 2 (Y-1) ≤ 3Y solution

3(y+1)>4y+2
3y+3>4y+2
-y>-1
∴y

System of quadratic inequalities 4x + 3Y ≤ 64 x + 2Y ≤ 38

After formula 2 × 4, the two formulas are subtracted to obtain y ≤ 88 / 5, which is substituted into any form to obtain x ≤ 24 / 5. Or by using the same method, the range of X is obtained by subtracting formula 2 × 3 from formula 2 × 2

Solving the equation 2Y ^ 2 + 4y-1 = 0.5 / 2Y ^ 2 + 2Y = 1 T ^ 2 + 2T = 5

2Y & # 178; + 4y-1 = 0 formula 2Y & # 178; + 4Y = 1 multiply both sides by 1 / 2Y & # 178; + 2Y = 1 / 2Y & # 178; + 2Y + 1 = 1 / 2 + 1 (y + 1) & # 178; = 3 / 2Y + 1 = ± √ (3 / 2) y + 1 = ± (√ 6) / 2Y + 1 = (√ 6) / 2 or y + 1 = - (√ 6) / 2y1 = (√ 6-1) / 2Y2 = - (√ 6 + 1) / 25 / 2Y & # 178; + 2Y = 1 multiply both sides by 2 /

0.4y+0.9/0.5 - 0.3-0.2y/0.3=1
(0.4y+0.9)/0.5 - (0.3-0.2y)/0.3=1

0.4y+1.8-0.3-2y/3=1
0.4y+1.5-2y/3=1
1.2y+4.5-2y=3
y=15/8

··0.4y + 0.9/0.5-y-5 / 2 = 0.3 + 0.2y/0.3 for y

The original formula is: 0.4y + 0.9/0.5-y-5 / 2 = 0.3 + 0.2y/0.3?
Multiply left and right by 30 to get:
12y+54-30y-75=10+20y
38y=31
y=31/38

Given x ^ 2-2y-1 = 0, then 2x ^ 2-4y + 3 =?

x^2-2y-1=0
Both sides at the same time * 2
2x^2-4y-2=0
2x^2-4y=2
2x^2-4y+3=5

If 2x + 4Y + 3 = 0, then x + 2Y + 1 = ()

-1
You will find that the left side can become 2x + 4Y + 2 = - 1
X 2 on the right is exactly 2x + 4Y + 2
Thank you

It is known that 4y-1 and 5-2y are opposite to each other, and the value of Y is obtained

4y-1 and 5-2y are opposite numbers
therefore
4y-1+5-2y=0
2y=-4
y=-2