The univariate quadratic equation 2x ^ 2 - (M + 1) x + 1 = x (x-1) is reduced to a general form The answer is x ^ 2-mx + 1 = 0

The univariate quadratic equation 2x ^ 2 - (M + 1) x + 1 = x (x-1) is reduced to a general form The answer is x ^ 2-mx + 1 = 0

2x²-(m+1)x+1=x(x-1)
To get rid of the brackets:
2x²-mx-x+1=x²-x
The result of the transfer is as follows:
2x²-x²-mx-x+x+1=0
So:
x²-mx+1=0

The equation (5-2x) (x + 1) = the square of 2x + 4 is transformed into the general form of quadratic equation with one variable
What is the coefficient of the quadratic term_____ The coefficient of the first term is______ The constant term is

(5-2x) (x + 1) = the square of 2x + 4
-2x²+3x+5=2x²+4
4x²-3x-1=0
The coefficient of the quadratic term is 4, the coefficient of the primary term is - 3, and the constant term is - 1

(16-2x) (12-2x) = 96

Divide both sides of the equation by 4 to get (8-x) (6-x) = 48. Note that the difference between 8-x and 6-x is 2, and 48 = 6 * 8 or = - 8 * (- 6), so 6-x = 6, x = 0 or 6-x = - 8, x = 14. After testing, both of them satisfy the problem, and there are at most two solutions to the univariate quadratic equation, so x = 0 or x = 14 is the

13-2x + 9x = 33.3

-2X+9X=33.3-13
7X=20.3
X=20.3/7
X=2.9