How to calculate x ^ 2-3x + 2 = 0

How to calculate x ^ 2-3x + 2 = 0

x^2-3x+2=0
(x-2)(x-1)=0
X = 2 or x = 1

Calculate 1 / 2 √ 16x-9 √ X / 4 + 3x √ 1 / X (x > 0)

1/2√16x-9√x/4+3x√1/x(x>0)
=(1/2)×4√x-9×√x/2+3√x
=2√x-9√x/2+3√x
=√x/2;
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How to shift the term of 3x's square + 8x = - 3? How to shift the term of 3x's square + 8x = - 3?

How to shift the term if the square of 3x + 8x = - 3?
-3 to the left becomes + 3
Namely
The square of 3x + 8x + 3 = 0

40x-20-3x-6 = 8x + 16-4x + 2
It is known that the sum of the solution of the equation 1 / 2 (1-x) = 1 = K and the solution of 3 / 4 (x-1) - 3 / 5 (3x + 2) = K / 10-2 / 3 (x-1) about X is 0, and the value of K is obtained

40x-20-3x-6=8x+16-4x+2
40x-3x-20-6=8x-4x+16+2
37x-26=4x+18
37x-4x=18+26
33x=44
3x=4
x=4/3