Read the following process before answering the question: solve equation (X-2) (x + 3) = 6 X-2 = 6, x + 3 = 6, x 1 = 8, x 2 = 3 Please judge whether the above process is correct? If not, please write the correct process

Read the following process before answering the question: solve equation (X-2) (x + 3) = 6 X-2 = 6, x + 3 = 6, x 1 = 8, x 2 = 3 Please judge whether the above process is correct? If not, please write the correct process

Incorrect problem solving process
Correct solution: (X-2) (x + 3) = 6
First expand the factor to get X & # 178; + X-6 = 6
If we move the term again, we get X & # 178; + X-12 = 0
The factorization results in (x-3) (x + 4) = 0
So, X1 = 3, X2 = - 4

Read the following process: solve the equation: | 5x | = 2
(1) When 5x is greater than 0, the original equation can be reduced to a linear equation of one variable 5x = 2, and the solution is x = 2 / 5;
(2) When 5x ＜ 0, the original equation can be reduced to a linear equation of one variable - 5x = 2, and the solution is x = - 2 / 5
Please follow the example above and solve the equation 3 | X-1 | - 2 = 10

3|x-1|-2=10
3|x-1|=10+2
3|x-1|=12
|x-1|=4
When X-1 > 0, the original equation can be reduced to a linear equation with one variable: X-1 = 4, and the solution is x = 5
When X-1

Solving equation (5x-1) / 6 = - 3 / 7 has a problem-solving process

(5X-1)/6=-3/7
Solution:
7(5X-1)=-18
35X-7=-18
35X=-11
X=-11/35