X ^ - 9x + 20 = 0 by factorization

X ^ - 9x + 20 = 0 by factorization

(x-4)(x-5)=0

Factorization: the square of X - 9x + 20

x^2-9x+20
=(x-4)(x-5）

Factorization 6x ^ 2-xy-2y ^ 2-x + 10y-12

6x^2-xy-2y^2-x+10y-12
=(2x + y) (3x-2y) - x + 10y-12 (the first cross multiplication)
=(2x + Y-3) (3x-2y + 4) (the second cross multiplication)
The first cross multiplication
2x y
×
3x ﹣ 2y
The second cross multiplication
2x＋y ﹣ 3
×
3x－2y 4

Factorization problem, the problem below, to solve the process
In recent years, our district has gradually increased the intensity of pollution control, and the streets and rivers have gradually become clear. A street needs to lay a sewage discharge pipeline with a total length of 1000 meters. In order to minimize the inconvenience of construction to urban traffic, in actual construction, we improved the construction scheme, laying 30% more than the original plan every day. As a result, the pipeline was laid 5 days ahead of schedule. How many meters of pipeline was laid in the original plan every day?

Let x = 5 + [1000 / (x * (1 + 30%)] be solved to get x = 600 / 13. X is the original plan of laying 600 / 13 meters per day according to the original fractional equation

To decompose the factor 4x ^ 4-9x ^ 2Y ^ 2 + 4Y ^ 4, please complete the remaining decomposition according to this idea. The original solution = 4x ^ 4-8x ^ y ^ 2 + 4Y ^ 4-x ^ = (2x ^ 2-2y ^ 2) ^ 2 - (XY) ^ 2

Original formula = 4x ^ 4-8x ^ y ^ 2 + 4Y ^ 4-x^
=（2X^2-2Y^2)^2-(xy)^2
=（2X^2-2Y^2+xy)（2X^2-2Y^2-xy)

Factorization 4x ^ 4-4y ^ 4

Original formula = 4 (x ^ 4-y ^ 4)
=4(x²+y²)(x²-y²)
=4(x²+y²)(x+y)(x-y)

4X ^ 4-12x ^ 3 + 9x ^ 2 (factorization)

4x^4-12x^3+9x^2
=x^2(4x^2-12x+9)
=x^2(2x-3)^2

If the equation AX ^ 2-2x ^ 2 = 2 about X is a quadratic equation with one variable, then the value of a is ()
If the equation AX ^ 2-2x ^ 2 = 2 about X is a quadratic equation with one variable, then the value of a is ()
A. 2 b. - 2 c.0 D. is not equal to 2

ax^2-2x^2=2
（a-2）x^2=2
First D, not 2

If the equation x ^ 3 + 2x ^ 2-1 = ax ^ 3-A + 7x is a quadratic equation of one variable with respect to x, then a =? What is the solution of the equation?

(1-a)x³+2x²-7x+(a-1)=0
If it is a quadratic equation of one variable, then the coefficient is 0
So 1-A = 0
a=1
So the equation is 2x & # 178; - 7x = 0
x(2x-7)=0
x=0,x=7/2

Quadratic equation of one variable 2x ^ 2 + 5x + 1 = 0, α + β = - 5 / 2, α * β = 1 / 2, find (α + 2) * (β - 2), α ^ 2 - β ^ 2

Because α + β = - 5 / 2, α * β = 1 / 2, α and β are two of the equations, and both are negative roots; when α > β, α - β = √ (α - β) ^ 2 = √ [(α + β) ^ 2-4 α * β] = √ [(- 5 / 2) ^ 2-4 * 1 / 2] = (√ 17) / 2 (α + 2) * (β - 2) = α * β - 2 (α - β) - 4 = 1 / 2 - √ 17-4 = - 7 / 2 - √ 17; α ^ 2 -