![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Given the quadratic function y = -- X ^ 2 + 4, when - 2 ≤ x ≤ 3, find its minimum value
-5
If y = 3 (x-1) (x + 2), then=____ The minimum value of Y is 0=_____
If y = 3 (x-1) (x + 2), then=__ -1/2__ The minimum value of Y is 0=__ -27/4___
I wish you happy! Hope to help you, if you do not understand, please ask, I wish learning progress_ ∩)O
What is the minimum value of quadratic function y = (x + 1) ^ - 2
y=(x+1)^-2
When x = - 1
The minimum value of Y is - 2
The minimum value of quadratic function y = (x-1) 2 + 2 is ()
A. -2B. 2C. -1D. 1
∵ (x-1) 2 ≥ 0, ∵ y = (x-1) 2 + 2 ≥ 2, ∵ the minimum value is 2
RELATED INFORMATIONS
- 1. The minimum value of quadratic function y = (x-1) 2 + 2 is () A. -2B. 2C. -1D. 1
- 2. It is known that the function f (x) satisfies f (2x-3) = 4x ^ 2 + 2x + 1 1 to find the analytic expression of F (x) 2 g (x) = f (x + a) - 7x, a is a real number, try to find the minimum value of G (x) in 1,3 closed interval
- 3. Known function f (x) = a INX + x ^ 2 (a is a real constant) (1) If a = - 2, prove that f (x) is an increasing function on (1, positive infinity); (2) find the minimum value of the function on [1, e] and the corresponding x value; (3) if x belongs to [1, e] so that f (x) is less than or equal to (a + 2) x, please try not to use special symbols to find the value range of real number a,
- 4. Let f (x) be an even function on R, and f (x + 3) = - 1 / F (x), and if - 3 ≤ x ≤ - 2, f (x) = 4x, then the value of F (2014)
- 5. The minimum value of function y = x + 2x + 2 / x + 1 (x ＞ - 1)
- 6. Given that the definition domain of function f (x) = 2asin (2x + π / 3) + B is [- π / 6, π / 6], the maximum value of function is 2 and the minimum value is 0, find the value of a and B
- 7. It is known that the domain of definition of the function f (x) = 2asin (2x - one third π) + B is r, the maximum value of the function is 2, and the minimum value is - 6
- 8. Let f (x) = 2x-1 (x)
- 9. (x+3y)(_____ )=9y^2 -x^2.
- 10. If 3Y = x + 2Z, then x ^ 2 + 9y ^ 2 + 4Z ^ 2-6xy-12yz + 4XZ=
- 11. If the minimum value of quadratic function y = x ^ 2 + 4x + A is 2, then the value of a is 2__
- 12. The minimum value of quadratic function x2 + 4x + 1
- 13. The domain of definition of function f (x) is d. if f (x1) ≤ f (x2) exists for any x1, X2 ∈ d when X1 < X2, then function f (x) is called non decreasing function on D, Let f (x) be a non decreasing function on [0,1] and satisfy the following three conditions: ① f (0) = 0, ② f (1-x) + F (x) = 1, ③ f (x / 3) = 1 / 2F (x), then the value of F (1 / 3) + F (5 / 12) is___________ .
- 14. Given the function f (x) = sin2x + acos2x (a ∈ R), and π / 4 is the zero point of the function y = f (x). (1) find the value of a, and find the function f (x) It is known that the function f (x) = sin2x + acos2x (a ∈ R), and π / 4 is the zero of the function y = f (x) (1) Find the value of a and the minimum positive period of function f (x); (2) If x ∈ [0, π / 2], find the range of function f (x)
- 15. Given the function f (x) = (k ^ 2 + 1) x ^ 2-2kx - (k-1) ^ 2 (K ∈ R), X1 and X2 are the two zeros of F (x), and X1 > x2（ Given the function f (x) = (k ^ 2 + 1) x ^ 2-2kx - (k-1) ^ 2 (K ∈ R), X1 and X2 are the two zeros of F (x), and X1 > x2 (1) (I) prove: X1 = 1; (II) find the value range of x2; (2) Let g (k) be the minimum value of function f (x). When x 2 ∈ [- 2, - 1], find the maximum value of G (k)
- 16. It is known that f (x) = x & sup2; - (K-2) x + K & sup2; + 3K + 5 has two zeros if the two zeros of the function are α and β, Find the value range of α & # 178; + β & # 178
- 17. Let f (x) be a quadratic function, and f (x-1) + F (2x + 1) = 5x ^ 2 + 2x, find f (x)
- 18. Let f (x) = 2mcos ^ 2x-2 √ 3msinx * cosx + n (M > 0) be defined as [0, Pai / 2] range [1,4] (1) (2) if f (x) = 2, find X
- 19. Find the definition field (1) f (x) = loga (1 + 3x-4x ^ 2) (a > 1 and a ≠ 1); (2) f (x) = [LG (2x ^ 2 + 5x-12)] / √ (x ^ 2-3)
- 20. Function equation f (x) - 2F (- x) = x ^ 2-5x, find f (x) The solution given by the answer is to construct another equation f (- x) + 2F (x) = x ^ 2 + 5x, but I don't know the basis of such construction?