The minimum value of quadratic function y = (x-1) 2 + 2 is () A. -2B. 2C. -1D. 1

∵ (x-1) 2 ≥ 0, ∵ y = (x-1) 2 + 2 ≥ 2, ∵ the minimum value is 2

Finding the definition field of function f (x) = 4x + 1 / 3

If the denominator is not 0, then the definition field is {x, X is not equal to - 3 / 4}

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