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Let f (x) = 16 / x ^ 2 + 8 (x is greater than 0) find the maximum value of F (x), and the denominator is x ^ 2 + 8. It is proved that f (x) < B ^ 2-3b + 21 / 4 for any real number B
The title is wrong
The molecule has X
f(x)=16/(x+8/x)
x+8/x>=2√(x*8/x)=4√2
f(x)=3
Because f (x)
If the real number x, y satisfies x ^ 2 + y ^ 2 = 3, then the maximum value of Y / x + 2
But I can't understand the △ why > = 0?
Because (x, y) is a point on a circle, so after substituting y = K (x + 2) into the circle equation, there must be a solution
Otherwise (x, y) will not satisfy the condition of x ^ 2 + y ^ 2 = 3
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