Given that s is the same, V1: V2: V3 = 2:3:5, find T1: T2: T3

Let V1 = 2x, V2 = 3x, V3 = 5x
According to the formula: S = VT,
So S1 = S2 = S3
So: v1t1 = v2t2 = v3t3
2xt1=3xt2=5xt3
Then we can calculate T1: T2: T3 = 15:10:6
(I haven't touched physics for a long time, so I'm not sure about it, am I right

Why v = at? Not that Delta V = at? T1: T2: T3 = 1: radical 3: radical 2, then why V1: V2: V3 = T1: T2: T3?

Yes, Δ v = at
But when the initial velocity is zero, v = at,
Because when the initial velocity is zero, Δ v = vt-0 = at
For the derivation of common formulas, see my answer

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