The acceleration of a car is 6m / S2 when it is in emergency braking on a road. If it has to stop within 2S, the maximum speed of the car can not exceed () A. 10m/sB. 12m/sC. 14m/sD. 13m/s

The acceleration of a car is 6m / S2 when it is in emergency braking on a road. If it has to stop within 2S, the maximum speed of the car can not exceed () A. 10m/sB. 12m/sC. 14m/sD. 13m/s


According to the reverse thinking, if the car moves in a straight line with uniform acceleration and zero initial speed, then v = at = 12m / s



A car runs 23 miles along the straight road at the speed V1, and then runs the remaining 13 miles at the speed V2 = 20km / h. If the average speed of the car for the whole journey is 28km / h, what is the speed of the car in the first 23 miles?


Suppose the whole journey is x, the average speed formula can calculate the time of the whole journey and the last 13 journey is t = XV, T2 = X320, then the time of the first 23 journey is T1 = t-t2 = xv-x320 = x28-x60 = 2x105 & nbsp; & nbsp; & nbsp; & nbsp; so V1 = 2x3t1 = 35 & nbsp; km / h, a: the speed of the first 23 journey is 35 km / h



Two straight roads intersect at an angle A. two cars drive along the two roads at the speed of V1 and V2 respectively. What is the speed of one car relative to the other?


Take one of the cars as the reference object, you might as well choose v1. Because the speed direction of the two cars is vertical, the other car relative to the reference object has not only the original V2 speed, but also a - V1 speed (because the direction is opposite), so the combined speed is the vector sum of V1 and V2, and its size is the square sum of V1 and V2 and then the root, that is, the square of V1 under the root plus the square of v2