U = {x | x = 2N-1, n ∈ n +, n less than or equal to 7}, a ∩ (cub) = {3,7}, CUA ∩ B = {9,13}, CUA ∩ cub = {1,11}, find a, B

U = {x | x = 2N-1, n ∈ n +, n less than or equal to 7}, a ∩ (cub) = {3,7}, CUA ∩ B = {9,13}, CUA ∩ cub = {1,11}, find a, B

U = {x | x = 2N-1, n ∈ n +, n less than or equal to 7} = {1,3,5,7,9,11,13}
If a ∩ (cub) = {3,7}, 3,7 belongs to a, not to B
CUA ∩ B = {9,13} 9,13 belongs to B, not to a
CUA ∩ cub = {1,11} leads to a ∪ B = {3,5,7,9,13}
A = {3,7} or {3,5,7}, B = {9,13} or {5,9,13} can be obtained
Also, when a = {3,7}, B = {9,13}, a ∪ B ≠ {3,5,7,9,13} (rounding)
When a = {3,5,7}, B = {9,13}, a ∩ (cub) = {3,5,7} ≠ {3,7} (rounding)
When a = {3,7}, B = {5,9,13}, CUA ∩ B = {5,9,13} ≠ {9,13} (rounding)
So a = {3,5,7}, B = {5,9,13}

The complete set u = R, a = {x ｜ X & # 178; > 4}, B = {x ｜ x ＞ 3}, finding a ∪ B, a ∩ B, CUA ∩ B, a ∪ cub
The complete set u = R, a = {x ｜ X & # 178; > 4}, B = {x ｜ x ＞ 3}, finding a ∪ B, a ∩ B, CUA ∩ B, a ∪ cub

A∪B ={x｜x2}
A∩B={x｜x＞3}
CUA ∩ B = empty set
A∪CuB=R

Given the complete set u = a ∪ B = {x ∈ n | 0 ≤ x ≤ 10}, a ∩ (∁ UB) = {1, 3, 5, 7}, find the set B

U = a ∪ B = {x ∈ n | 0 ≤ x ≤ 10} = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, {1, 3, 5, 7} ⊆ a, but B does not contain {1, 3, 5, 7}, which is represented by Venn graph, as shown in the figure ∪ B = {0, 2, 4, 6, 8, 9, 10}

Given the complete set u = AUB = {x ∈ n ∣ 0 ≤ x ≤ 10}, a ∩ (cub) = {1,3,5,7}, try to find the set B
It must be very detailed, otherwise I can't understand

U=A∪B=｛0,1,2,3,4,5,6,7,8,9,10｝.
∵A∩（CuB）=｛1,3,5,7｝,
The elements 1,3,5,7 belong to set a, and 1.3.5.7 also belong to the complement of set B
Cub = {1,3,5,7}, which means that the B set does not contain 1.3.5.7,
So b set should be the number contained in all complete sets except 1.3.5.7
∵U=A∪B,
∴B=｛0,2,4,6,8,9,10｝