Two real roots x1, X2 of 2 + 2x + T (t is all real numbers), if lx1l + lx2l = f (T), find the analytic expression of function f (T) (x ~ 2 is the root of x)

Two real roots x1, X2 of 2 + 2x + T (t is all real numbers), if lx1l + lx2l = f (T), find the analytic expression of function f (T) (x ~ 2 is the root of x)


As a result, we are going to have the following [4-4t = 4-4t ≥ 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t (t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t = 4-4t (t = 4-4t = 4-T = 4-T = 4-4t ≤ 4-4t = 4 (t = 4-4t = 4-4t = 4-4t ≥ 0 ||||||||||||||||||124;||\|124;1244-4t is f (T) = 2 radical (1-T)



Given that the derivative of F (x) is f '(x), and 2F (x) + XF' (x) > x ^ 2, then
Given that the derivative of F (x) is f '(x), and 2F (x) + XF' (x) > x ^ 2, then
A.f(x)>0 B .f(x)x D.f(x)x


Because 2F (x) + XF '(x) > x ^ 2 ① The following is discussed: (1) when x = 0, substitute ① to get: when f (0) > 0 (2) x > 0, both sides of ① multiply X: 2xf (x) + x ^ 2F '(x) > x ^ 3, that is [x ^ 2F (x)]' > x ^ 3 > 0, so the function y = x ^ 2F (x) is an increasing function on R +, and x > 0



The following statement is correct ()
A. X = 4 is a solution of inequality 2x > - 8. B. x = - 4 is the solution set of inequality 2x > - 8. C. the solution set of inequality 2x > - 8 is x > 4D. The solution set of inequality 2x > - 8 is x < - 4


Because the solution of 2x > - 8 is x > - 4, so a and x = 4 are solutions of inequality 2x > - 8, correct; B and x = - 4 are solutions of inequality 2x > - 8, wrong; C and 2x > - 8 are solutions of inequality x > 4, wrong; D and 2x > - 8 are solutions of inequality x < - 4, wrong



Are the two statements "the solution of inequality 2x + 3 > 1 is x = 3" and "x = 3 is the solution of inequality 2x + 3 > 1" correct?


The statement that "the solution of inequality 2x + 3 > 1 is x = 3" is wrong. There is only a solution set for inequality. Unless there is only one value, it can not be used;
"X = 3 is the solution of inequality 2x + 3 > 1" is right. X = 3 satisfies 2x + 3 > 1, so it is one of the values in the solution set of inequality. Strictly speaking, "x = 3 is a solution of inequality 2x + 3 > 1"