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Given that x = - 1 is the root of the equation AX2 + BX + C = 0 (B ≠ 0), then AB + CB = () A. 1B. -1C. 0D. 2
∵ x = - 1 is the root of the equation AX2 + BX + C = 0, ∵ A-B + C = 0, that is, a + C = B, ∵ AB + CB = a + CB = BB = 1
Given that y is equal to the square of AX + BX + C, when x = 1, y = 6, when x = - 1, y = 2, when x = 3, y = 34, what is the value of y when x = - 3
y=ax^2+bx+c
a+b+c=6
a-b+c=2
9a+3b+c=34
This is the linear equation with three variables. The solution is a = 3, B = 2, C = 1;
So when x = - 3, y = 22
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