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As shown in the figure, the inscribed circle I of equilateral triangle ABC is tangent to each side and the point def, the radius of the inscribed circle is 1, and the side length of the triangle is calculated There is no picture. I'm sorry. I'll make do with it,
A vertex of an equilateral triangle, the center of the inscribed circle, and the tangent point of one side form a right triangle with an acute angle of 30 degrees. The side length of the triangle is radical 3 * 1 * 2 = 2 radical 3
In the triangle ABC, ∠ C = 90 °, AB, AC and BC are 10cm, 6cm and 8cm respectively
The teacher said to solve the equation with one variable,
The equation of first degree with one variable,
Let the distance be X
The area formula of triangle can be known as = 1 / 2 * ac * BC = 1 / 2 * AB * X
Namely: 1 / 2 * 6 * 8 = 1 / 2 * 10 * x
X = 4.8cm
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