Fold rectangle ABCD along AE so that point B falls on median line FG of right angled trapezoid AECD, and ab = root 5, then what is the length of AE? (trapezoid in rectangle) AE is trapezoidal bevel (waist)
In the triangle AB "F, AB" = AB = radical 5, FB "= (radical 5) / 2, AF = (radical 15) / 2 = EB is obtained according to Pythagorean theorem. Let be = x, then EF = x / 2. Triangle Abe area = AB * be / 2 = (radical 5) x / 2, triangle AB" e area = FB *
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- 1. As shown in the figure, in the isosceles trapezoid ABCD, ad is parallel to BC, angle B = 45 degrees, AE is perpendicular to BC, and point E, AE = ad = 2cm
- 2. In the isosceles trapezoid ABCD, the angle B is 60 degrees, ad is parallel to BC, and the angle BAC is equal to 90 degrees. The median line length of the isosceles trapezoid is 12cm. Find the circumference of the isosceles trapezoid
- 3. In the triangle ABC, ab = AC, EF is the median line of the triangle ABC, intersecting AB, AC at e, f respectively, extending AB to D, making BD = AB, connecting CD
- 4. In triangle ABC, ab = AC, EF is the median line of triangle ABC, extend AB to point D, make BD = AB, connect CD, what do you think is the relationship between CE and CD
- 5. As shown in the figure, ⊙ o, if the chord ad ∥ BC, Da = DC, ∠ AOC = 160 °, then ∠ BCO is equal to______ Degree
- 6. Let m.n be two points on the radius op of the ball 0 and NP = Mn = OM. Make three circles that are perpendicular to the surface of OP through m.n.o. respectively, then the area ratio of these circles is
- 7. It is known that the circle O and the circle K are the big circle and the small circle of the ball o, and their common chord length is equal to the radius of the ball o, OK = 3 / 2, and the angle between the circle O and the plane of the circle K is 60 degrees, Then the surface area of ball 0 is?
- 8. For the two strings AB and Cd in the circle O, AB > CD, the distances from the center O to AB and CD are OM and on respectively, then om on is filled with >< =
- 9. It is known that in ⊙ o, n is the midpoint of the chord AB, on intersects the arc AB in M, if AB = 2, radical 3, Mn = 1, the radius of ⊙ o is obtained
- 10. As shown in the figure, ⊙ O's chord AB and AC have an included angle of 50 °, Mn is the midpoint of arc AB and arc AC respectively, and OM and on intersect AB and AC at points E and f respectively, then the degree of ∠ mon is () A. 110°B. 120°C. 130°D. 100°
- 11. Ad is the median line of △ ABC, EF is the median line of △ ABC, then the quantitative relationship between EF and ad is__________ .
- 12. As shown in the figure, take sides AC and BC of △ ABC as one side respectively, and make square ACDE and cbfg outside △ ABC. Point P is the midpoint of EF. Prove that the distance from point P to AB is half of ab
- 13. M is the middle point of the side BC of the triangle ABC, and AB, AC are taken as the square ACDE and abgf to prove am = half EF
- 14. In the triangle ABC, ∠ a > 90 °, BD and CE are the heights of the triangle respectively, and M is the midpoint of the edge BC, connecting de and DM, (1) complete the drawing according to the above requirements (2) To prove that △ MDE is an isosceles triangle (3) try to explore whether △ MDE can be a right triangle? If yes, please tell us the degree of ∠ BAC
- 15. In the triangle ABC, the angle ACB is 90 degrees, and D is the intersection of the bisectors of the three interior angles of the triangle ABC. If AC = 3, BC = 4, find the distance from D to ab?
- 16. As shown in the figure, the inscribed circle I of equilateral triangle ABC is tangent to each side and the point def, the radius of the inscribed circle is 1, and the side length of the triangle is calculated There is no picture. I'm sorry. I'll make do with it,
- 17. As shown in the figure, in △ ABC, D, e and F are the points on AB, AC and BC respectively, and de ‖ BC, EF ‖ AB, ad: DB = 2:3, BC = 20cm, the length of BF can be obtained
- 18. As shown in the figure, there are two slides of the same length. The height AC of the left slide is equal to the length DF of the right slide in the horizontal direction. The relationship between the inclination angles ∠ ABC and ∠ DFE of the two slides is () A. ∠ABC=∠DFEB. ∠ABC>∠DFEC. ∠ABC<∠DFED. ∠ABC+∠DFE=90°
- 19. As shown in the figure, point G is the center of gravity of triangle ABC, Ge is parallel to AB, GF is parallel to AC Proof: GD is the middle line on the edge EF of the triangle GEF
- 20. In the triangle ABC, the angle BAC = 90 degrees, ab = AC = 6cm, point G is the center of gravity of the triangle ABC, making GD / / CB intersection AB with D, connecting AG, then s triangle GAD = multiple