For the two strings AB and Cd in the circle O, AB > CD, the distances from the center O to AB and CD are OM and on respectively, then om on is filled with >< =

For the two strings AB and Cd in the circle O, AB > CD, the distances from the center O to AB and CD are OM and on respectively, then om on is filled with >< =


The correct answer is: om < on



AB and CD are two strings on the circle O respectively. The distances from the center O to them are OM and on respectively. If AB is larger than CD, what are the sizes of OM and on


Om less than on can be easily seen by drawing a figure below, or from (chord length / 2) ^ 2 (distance from center to chord) ^ 2 = radius ^ 2 OM



If AB is larger than CD, what is the relationship between the size of OM and on?


OM is less than on



Arc Mn is an arc with o as the center, and the angle mon = 90 degrees. When passing through the midpoint a of Mn, make AB parallel to on and intersect Mn at point B, try to find the degree of the angle bon


Setting: 1
AB and Mo intersect at P,
A is the midpoint of Mn, AP / / No
=>
AP is the median line of mon,
PO=MP=1/2OM
Angle PbO = 90
=>
Even Bo
BO=2PO
=>
POB=60
=>
BON=30