Given that the function f (x) is an odd function on R, when x > 0, f (x) = log2 (1 + x), the inequality f (x0) about x0 is solved

Given that the function f (x) is an odd function on R, when x > 0, f (x) = log2 (1 + x), the inequality f (x0) about x0 is solved

The results were correct, but there was a problem at first
It is known that the function f (x) is an odd function on R. when x > 0, f (x) = log2 (1 + x). When the inequality f (x0) 0 about x0 is solved, f (x) = log (2,1 + x),
When x

F (x) is an odd function. When x belongs to (0, positive infinity), f (x) = log2, there is an X inequality on it to find the solution set of F (x) ＜ - 1?

F (x) = log (2) x (x > 0) when x