Electricity meter 3000r / kW. H, connected to a lamp, 3 minutes to 150r, how much energy does the bulb consume during this time

Electricity meter 3000r / kW. H, connected to a lamp, 3 minutes to 150r, how much energy does the bulb consume during this time

If the electric energy meter turns 3000r, it will consume 1 degree of electricity, so the electric energy consumed by 150r in 3 minutes is 150 / 3000 = 0.05kw. H

When two bulbs of the same specification are connected in series, do they have the same voltage and current
Can we get it directly

Two electric bulbs of the same specification have the same resistance and power, that is to say, two identical components are connected in series (you can take it as a resistance). Of course, you can directly draw the conclusion that the voltage and current are equal

Two bulbs with the same rated voltage and different rated power are connected in series in the same circuit. The bulb with lower rated power has higher actual power
Make it clear. Thank you

From P = u ^ 2 / R, we can know that under the condition of the same rated voltage, the bulb with higher rated power has lower resistance and the bulb with lower rated power has higher resistance. In the series circuit, the voltage drop of the consumer is proportional to its resistance, that is to say, the voltage drop on the bulb with higher resistance is higher than that on the bulb with lower resistance