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Is it OK for a 100 watt 220 volt bulb and a 40 Watt 220 negative bulb to jump in the 380 negative circuit? Why Who knows why you can and why you can't tell me how to calculate it? Thank you here I know, but can I take it? You didn't say that. I don't know what to do
The principle of upstairs is right. When it is connected in series in 380 V circuit, the circuit current should be 0.2243a
40W bulb voltage 271.43v, will burn
100W bulb voltage 108.56v
108.56+271.43=380V
Is it OK for a 100 watt 220 volt bulb and a 40 Watt 220 negative bulb to jump in the 380 negative circuit? Why?
How to calculate it
40W light bulb will burn out!
P=UI
I=U/R
=> R=UU/P
Resistance of 40W bulb = 220 * 220 / 40 = 1210
Resistance of 100W bulb = 220 * 220 / 100 = 484
When connected to 380V circuit:
40W bulb voltage = (380 / (1210 + 484)) * 1210 = 271.42v
40W bulb voltage = (380 / (1210 + 484)) * 484 = 108.57
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