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Two lamps with rated voltage of 220 V and power of 100 and 25 W respectively are connected in series in 380 V circuit Calculate the voltage distribution results of the two ends of the bulb respectively
Calculate the resistance of two bulbs by r = u * U / P, and then calculate the voltage by the principle of series voltage division
R1 = 220 * 220 / 100, R2 = 220 * 220 / 25, R2 = 4r1 without calculation, so two bulbs are connected in series, the voltage at both ends of 100W bulb is 76V, and the voltage at both ends of 25W bulb is 304v
If a 220 V 60 W bulb is connected with a 220 V 60 W bulb under 220 V voltage, what is the current in the trunk circuit and the electric power in the circuit?
Don't give direct results
The power is 60W + 60W = 120W
The current is 120W △ 220V = 0.5455a
The lamp voltage of 250W is 220V, and the current is 2 and 1a, right?
I=P/U=250/220=1.14A
This 1.14a means that when the lamp is in a stable state, there is a large surge current at the moment when the lamp is turned on (filament from cold state to hot state)
When a 220 V, 250 W bulb is connected to 193.6 V voltage, the current of the small bulb and the electric power consumed at this time are the same,
I level = 250 / 220, R lamp = 220 / I level = 193.6 Ω. I actual = 220 / R lamp = 1 A. P = 1 A * 193.6 v = 193.6 W
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