A 220 V, 1000 W electric kettle works for 30 min, how many kWh and j are consumed?

A 220 V, 1000 W electric kettle works for 30 min, how many kWh and j are consumed?


You have to know that a 1000W electric kettle consumes one degree of electricity in one hour. One degree of electricity is 3600000 joules. Half an hour is 1800000j



An electric iron is connected in the circuit of 220 V, and the current passing through it is 250 ma. If it is electrified for 1 hour, how much electric energy is consumed


W=Pt=3600*220*0.25=198000J



When an electric iron is connected to a 220 V circuit, it consumes 4620 J of electric energy per minute. At this time, the electric energy flowing through the electric iron is very low


w=UIt,I=w/Ut=0.37A



Connect a 220v200w electric fan, a TV set and an electric iron into the home circuit respectively. The power on time is the same. The current flows through them
Who has more heat?
I remember the heat formula is q = i2rt = Pt, I think it's the same


=The formula PT is only valid in pure resistance circuit. For TV and electric fan, it is obviously not pure resistance circuit. I think it can be understood that electric energy is the same, but TV and electric fan do not convert all electric energy into heat energy, and electric iron can be regarded as pure resistance circuit basically, so electric iron should generate the most heat