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If the lamp marked with "220 V & nbsp; & nbsp; 100 W" is connected to the home circuit and energized for 1 hour, the work done by the current is______ J. Its resistance is______ Ω．
When the electric lamp is connected to the home circuit, it can work normally, ∵ P = 100W, t = 1H = 3600s, ∵ the work done by the current is: w = Pt = 100W × 3600s = 3.6 × 105J, the resistance of the electric lamp is: r = u2p = (220V) 2100W = 484 Ω. So the answer is: 3.6 × 105484
What is the power of a 220 V, 100 W bulb if it is wrongly connected to the 380 V power supply?
Because the original: 100 = 220x220 / R
Later: P = 380x380 / R
P / 100 = 38x38 / 22 / 22 = 19x19 / 121
=298.3W
It's burning
Connect a 220 V, 40 W light bulb and a 220 V, 100 W light bulb in parallel and connect them to the 220 V power supply. Which light? Why? Why? In series?
Parallel, 220 V, 100 W, bright, series, 220 V, 40 W
Because the resistance of 220 V and 40 W is 1210 ohm, and that of 220 V and 100 W is 484 ohm, P is inversely proportional to R in parallel, and P is proportional to R in series
A 220V 100W lamp and a 220V 15W lamp are connected in series in the 380V circuit. Ask if the lamp is broken or not
None of them is broken. One resistor is 484, and the other is 3226380 divided by 484 + 3226 to get the main circuit current. After multiplying the respective resistors, we can get the actual partial voltage of the bulb, which should not be broken
RELATED INFORMATIONS
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