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Bulbs L1 and L2 are marked with "22ov 25W" and "220V 15W" respectively. If the two bulbs are connected in series, the voltage ratio of the two lamps is? The ratio of the actual power consumed is?
P=UI=U(U/R)=(U^2)/R
R=(U^2)/P
P1/R2=[(U^2)/P1]/[(U^2)/P2]=P2/P1=15/25=3/5
After the two bulbs are connected in series, the current I ᧄ, etc
Voltage U = IR
Voltage ratio = resistance ratio = 3:5
Actual power P = UI,
Cause I
So the actual power ratio = voltage ratio = resistance ratio = 3:5
If the voltage at both ends of a bulb is 220 V and the power consumed in 10 min is 3.6 times the fourth power of 10, then the power of the bulb is 220 v
What is the current through the bulb and the resistance of the filament
P=W/t=36000J/600s=60w
P=UI
I=P/U=60w/220v=0.27A
R=U/I=220V/0.27A=814.8Ω
When a washing machine is connected to a 220 V circuit, the power consumption for 10 minutes is 1.8 × 10 quintic J, and the electric power of the washing machine is calculated
(1.8*10^5)/600=180000/600=3000W
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