If the resistance ratio of the two electric heaters is 3:2 and they are connected to the lighting circuit, and they all work normally, what is the ratio of heat generated by them and the ratio of work done by the current in the same time?

If the resistance ratio of the two electric heaters is 3:2 and they are connected to the lighting circuit, and they all work normally, what is the ratio of heat generated by them and the ratio of work done by the current in the same time?

If the two resistors are in parallel
1. Because the time is the same, the voltage is the same,
So from the formula q = (u ^ 2 / R) * t
So Q1: Q2 = R2: R1 = 2:3
2. Because it is pure resistance, q = W
So the ratio of work done by current is also 2:3
If two resistors are in series
1. Because the time is the same, the current is the same,
So from the formula q = I ^ 2rt
So Q1: Q2 = R1: R2 = 3:2
2. Because it is pure resistance, q = W
So the ratio of work done by current is also 3:2
Please click adopt. If you are not sure, you can ask

When the electric heater works normally, the resistance is 1050 ohm, the current is 0.5 A, the heat per minute is 15750 coke, the working rate is 262.5 W, and the heat generated heats 1 kg of water, how much degree Celsius does it increase

Δt=Q/cm=15750J/(4.2×10³J/(kg.℃)*1kg)=3.75℃

Does the electrical power decrease when the resistance increases?
It can be seen from the increase of resistance that current decreases and voltage increases. P = UI, u increases and I decreases, then P increases or decreases? If the formula P = u ^ 2 / R, u ^ 2 increases and R increases, then P increases or decreases? Another formula is p = I ^ 2R, I decreases and I ^ 2 decreases and R increases, then P increases or decreases?
Downstairs. If so, I won't ask questions. The problem is that R changes, I changes, and u changes. I mean the voltage at both ends of the resistor. What if there are other resistors connected in series with it? If R increases, I will decrease?

There are some troubles in the process. Let me tell you the rules first
If the variable resistance is written as R and the constant resistance in series with it is written as R0, then:
When rr0, R increases, its power P decreases;
When r = R 0, its power P is the maximum
Have you studied quadratic function?