The rated voltage of a brand electric kettle is 220 V, 50 Hz, the rated power is 1100 W, and the capacity is 1.2 L 1 The rated voltage of a brand electric kettle is 220 V, 50 Hz The constant power is 1100W and the capacity is 1.2L 1. What is the resistance in normal operation? 2. The normal work is to boil a pot of water for 5 minutes. How much electricity is consumed? 3. When the voltage is only 200V, what is the actual power? Reserve one decimal place

The rated voltage of a brand electric kettle is 220 V, 50 Hz, the rated power is 1100 W, and the capacity is 1.2 L 1 The rated voltage of a brand electric kettle is 220 V, 50 Hz The constant power is 1100W and the capacity is 1.2L 1. What is the resistance in normal operation? 2. The normal work is to boil a pot of water for 5 minutes. How much electricity is consumed? 3. When the voltage is only 200V, what is the actual power? Reserve one decimal place

Electric kettle is generally made by pure resistance heating principle
1. So we can know that r = u squared / P = (220 * 220) / 1100 = 44 ohm according to P = UI = u squared / R
2. Electric energy:
In general, people often use "degree" to express: w = kW. H = 1.1KW * (5 / 60) = 0.0917 degree
Look back
The unit of electric energy is "degree". Its scientific name is kilowatt hour, and its symbol is kW · H
1 kwh = 6 joules of 3.6 * 10
In physics, the more commonly used unit of energy (that is, the main unit, sometimes called the international unit) is Joule, abbreviated as Joule, and the symbol is J
One joule equals one watt second
3. Still p = UI = u squared / R, now 200V, the resistance is 44 ohm because it is made of 220V and 50Hz
Then we can know: P = (200 * 200) / 44 = 909.1w
The answer is: 44 ohm, 0.0917 kwh, 909.1w
Do you think it makes sense

There is an electric kettle with the specification of 220 V and 1000 W. when the electric kettle works normally, how large is the resistance of the internal heating wire? Under the rated voltage, turn the 1kg 20 ℃ electric kettle
= =

R=Uˆ2/P=(220V)ˆ2/1000w=48.4Ω
The title is incomplete
Q suction = cm (t-t0) = 4.2 × 10 & # 710; 3j / (kg. ℃) × 1kg × (100-20) ℃ = 3.36 × 10 & # 710; 5J
Under the rated voltage, Q suction = q = I & # 710; 2rt = Pt, t = q suction / P = 3.36 × 10 & # 710; 5J / 1000W = 336s