If a bulb is marked with "220 V 100 W" and B bulb is marked with "220 40 W", then: (1) the ratio of resistance when both a and B bulbs are normally emitting R A: R B=_______ The ratio of current passing through is I a: I b=________ , the ratio of power consumption P A: P=_________ . (2) Connect a and B bulbs in series and connect them in a 220 V circuit. The voltage ratio at both ends of the two bulbs is u a: u B=_________ The brighter one is____ Light bulb: (3) Connect the two bulbs A and B in parallel in a 220 V circuit, and the current ratio at both ends of the two bulbs is I a: I b=________ The brighter one is____ Light bulb:

If a bulb is marked with "220 V 100 W" and B bulb is marked with "220 40 W", then: (1) the ratio of resistance when both a and B bulbs are normally emitting R A: R B=_______ The ratio of current passing through is I a: I b=________ , the ratio of power consumption P A: P=_________ . (2) Connect a and B bulbs in series and connect them in a 220 V circuit. The voltage ratio at both ends of the two bulbs is u a: u B=_________ The brighter one is____ Light bulb: (3) Connect the two bulbs A and B in parallel in a 220 V circuit, and the current ratio at both ends of the two bulbs is I a: I b=________ The brighter one is____ Light bulb:


A bulb is marked with "220 V 100 W". B bulb is marked with "220 40 W", then: (1) the ratio of resistance R A: R B = (2:5), the ratio of current I a: I B = (5:2), and the ratio of power consumption p a: P = (5:2) when both a and B bulbs are normally emitting



How many hours does a 220 volt, 100 watt bulb consume 1 kilowatt hour


10 hours, 1 kilowatt hour = 1 kilowatt hour = 0.1kwx10h



A classmate of an extracurricular group made a self-made electric iron. The rated voltage is 220 v. when working under the rated voltage, the resistance is 1210 Ω, and its rated power is 0______ W. Power on for 10 min at rated voltage______ J heat


(1) P value = U2 value, r = (220 V) 21210 Ω = 40 W; (2) ∵ when the electric iron works under the rated voltage, ∵ P = P value = 40 W, ∵ heat generated after 10 min of power on: Q discharge = w, electricity = Pt = 40 W × 10 × 60 s = 24000 J



Urgent: a lamp is marked with the words "220 V, 110 W", ask: (1) how much is the current when the lamp works normally? (2) how much is the resistance of the lamp?
(3) If connected to a 110V circuit, what is the actual power of the lamp?


I=P/U=110W/220V=0.5A
R = u ^ 2 / P = (220 V) ^ 2 / 110 w = 440 Ω
P = u '^ 2 / r = (110V) ^ 2 / 440 Ω = 27.5w