A power is 400W, the voltage of 220 V rice cooker, how much electricity consumption in three hours?

A power is 400W, the voltage of 220 V rice cooker, how much electricity consumption in three hours?

What we usually say is kilowatt hour kWh
Electric cooker power P = 400W = 0.4KW
E = Pt = 0.4 * 3kwh = 1.2kwh, i.e. 1.2 kwh for 3 hours

Today, there is a 40W fluorescent lamp. When it is used, the lamp tube and ballast (which can be regarded as pure inductance approximately) are connected in series. The voltage is 220 V and the frequency is 50 Hz
It is known that when the lamp works, it belongs to pure resistance load. The voltage at both ends of the lamp is 110V. Try to find the inductance and inductance of the ballast. At this time, what is the green factor of the circuit? If the power factor is increased to 0.8, how much capacitance should be paralleled

Original power factor cos φ 0 = 110 / 220 = 0.5, φ 0 = arccos 0.5 = 60 ° new power factor cos φ = 0.8, φ = arccos 0.8 = 36.9 ° compensation capacitor C = P / (ω u ^ 2) (Tan φ 0-tan φ) = 40 / (314x220 ^ 2) (Tan 60 ° - Tan 36.9 °) = 40 / 15197600 (1.732-0.751) = 2.58x10 ^ - 6F = 2.58 μ f

If the power factor of the fluorescent lamp circuit is known to be 0.45, the power supply voltage is 220 V, and the lamp tube voltage is 98 V, what is the estimated voltage at both ends of the ballast?

Let the lamp be a pure resistor R, and the ballast be an inductance L + resistor R0: cos φ = 0.45, φ = 63.3 ° have the following formula: (ur + ur0) / 220 = cos63.3 °, UL / 220 = sin63.3 ° ur + ur0 = 220 × cos, φ = 99 V, ur0 = 99-98 = 1 V, UL = 220sin63.3 ° = 196.5 V, so the voltage at both ends of the ballast = root (square u

How many degrees is the voltage of 220V 1.3A

The voltage of 220V 1.3A is equal to 220x1.3 = 286w = 0.286kw
286 kwh per hour,
86 kwh in 10 hours,
286 kwh per 1000 hours,