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A "220 V, 1000 W" electric furnace is connected to 110 V voltage to make it consume 1000 W power. The following methods are feasible A connect half of the wire to the circuit B. lengthen the electric furnace wire to twice the original length and connect it to the circuit C connect 1 / 4 of the wire to the circuit D connect 3 / 4 of the wire to the circuit
C
If P = u & # 178 / R, u & # 178; is 1 / 4 of the original, then r should be 1 / 4 of the original
Obviously, 1 / 4 can be connected to the circuit
R = resistivity * L / s, if the elongation is 2 times, the cross-sectional area becomes 1 / 2 of the original, R '= resistivity * 2L / (1 / 2S) = 4R, which is not qualified
Connect an electric heater marked with "220 V, 100 W" to a certain power supply, and it will emit 54000 joules of heat in 10 minutes. What's the time?
What is the output power?
What is the voltage at both ends of the electric heater?
How many joules of heat are emitted in 20 minutes?
The rated voltage is 220 V, the rated power is 100 W, so the working current is 5 / 11 a
So the working current is 5 / 11a
Power P = w / T
P=54000/(60*10)=90W
W=UI
U=W/I=90/(5/11)=198V
Joule heat for 20 minutes = w * t = 90 * (60 * 20) = 108000
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